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  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main - Mock Test - 11

  • question_answer
    The current through a bulb is increased by 1%. Assuming that the resistance of the filament remains unchanged the power of the bulb will

    A) increase by 1%

    B) decrease by 1%

    C) increase by 2%  

    D) decrease by 2%

    Correct Answer: C

    Solution :

    \[P={{I}^{2}}R.\] Hence \[\frac{dP}{P}=\frac{2dI}{I}.\] Since \[\frac{dI}{I}=1%\]% Hence \[\frac{dP}{P}=2%\]%


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