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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 11

  • question_answer
    Let \[f(x)=\sqrt{\frac{{{x}^{2}}+px+1}{{{x}^{2}}-p}}\]. If \[f(x)\] is discontinuous at exactly two values of x, then number of integers in the range of p is

    A) 1                                 

    B) 2                

    C) 3                       

    D) 4

    Correct Answer: B

    Solution :

    [b] For two points of discontinuity, \[p>0\] and \[{{x}^{2}}+px+1\ge 0\,\,\,\forall \,\,\,x\in R\]  \[\therefore \,\,{{p}^{2}}-4\le 0\] \[\therefore \,\,p\in [-2, 2]\] \[\therefore \,\,p\in (0, 2]\] Hence, number of integers is 2.  


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