A) \[\frac{\pi {{v}^{2}}}{g}\]
B) \[\frac{\pi {{v}^{4}}}{{{g}^{2}}}\]
C) \[{{\pi }^{2}}\frac{{{v}^{4}}}{{{g}^{2}}}\]
D) \[\frac{{{\pi }^{2}}{{v}^{4}}}{{{g}^{2}}}\]
Correct Answer: B
Solution :
Maximum possible horizontal range \[={{v}^{2}}/g\] Maximum possible area of the circle \[=\pi {{\left( \frac{{{v}^{2}}}{g} \right)}^{2}}=\frac{\pi {{v}^{4}}}{{{g}^{2}}}\]
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