JEE Main & Advanced Sample Paper JEE Main - Mock Test - 12

  • question_answer
    Which of the following is (are) CORRECT statements?
    (I) \[0.1\text{ }M\]\[CaC{{l}_{2}}\] has higher boiling point than\[0.1\text{ }M\]\[NaCl\].
    (II) \[0.05\text{ }M\]\[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]has higher freezing point than \[0.1\text{ }M\]\[{{K}_{3}}[Fe{{(CN)}_{6}}].\]
    (III) \[0.1\text{ }M\]glucose exerts higher osmotic pressure than \[0.08\text{ }M\]\[C{{H}_{3}}COOH\](\[25%\] dissociated).
    (IV) Vapour pressure of \[0.05\text{ }M\]urea solution is greater than that of \[0.05\text{ }M\text{ }KCl\]solution.
    The CORRECT choice is

    A)  I, III              

    B)  II, IV                     

    C)  I, II, III                 

    D)  I, II, IV

    Correct Answer: D

    Solution :

    [d] \[{{T}_{b}}\] is higher if im is higher \[{{T}_{f}}\]. is higher if im is lower, \[\pi \] is higher if im is higher. VP is higher if im is lower. \[CaC{{l}_{2}}:im=3\times 0.1;\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}:im=5\times 0.05;\] Glucose: \[im=1\times 0.1;\] \[NaCl:im=2\times 0.1;\] \[{{K}_{3}}[Fe{{(CN)}_{6}}]:im=4\times 0.1;\] \[C{{H}_{3}}COOH:im=(1+\alpha )m=1.25\times 0.08=0.1\] Urea: \[im=1\times 0.05;\] \[KCl:im=2\times 0.05=0.1\]


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