JEE Main & Advanced Sample Paper JEE Main - Mock Test - 12

  • question_answer
    The interval in which the function \[2{{x}^{3}}+15\] increases less rapidly than the function \[9{{x}^{2}}-12x,\] is

    A) \[(-\infty ,1)\]                

    B)   \[(1,2)\]

    C) \[(2,\infty )\]                 

    D)   None of these

    Correct Answer: B

    Solution :

    Let \[f(x)=2{{x}^{3}}+15\]  and \[g(x)=9{{x}^{2}}-12x\]then
    \[f'(x)=6{{x}^{2}}\,\forall \,x\in R\]
    \[\therefore \,\,f(x)\] is increasing function \[\forall \,x\in R\]
    Also, \[g'(x)>0\Rightarrow 18x-12>0\Rightarrow x>\frac{2}{3}\]
    Thus, \[f(x)\] and \[g(x)\] both increases for \[x>\frac{2}{3}\]
    Let \[F(x)=f(x)-g(x),\] \[F'(x)<0\]
    (\[\because \] \[f(x)\] increases less rapidly than the function g \[(x)\])
    \[\Rightarrow \,\,6{{x}^{2}}-18x+12<0\]
    \[\Rightarrow \,\,\,1<x<2\]


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