JEE Main & Advanced Sample Paper JEE Main - Mock Test - 12

  • question_answer
    In a triangle ABC, \[\tan \frac{A}{2}=\frac{5}{6}\]and \[\tan \frac{C}{2}=\frac{2}{5},\] then

    A) \[a,b,c\] are in A.P.

    B) \[\cos \,A,\,\cos B,\,\cos \,C\] are in A.P.

    C) \[\sin A,\sin B,\sin C\] are in A.P.

    D) [a] and [c] both

    Correct Answer: D

    Solution :

    Here \[\frac{A}{2}\,\tan \frac{C}{2}=\frac{s-b}{s}\] \[\frac{5}{6}.\frac{2}{5}=\frac{s-b}{s}\Rightarrow 3s-3b=s\Rightarrow 2s=3b\] \[\Rightarrow \,\,\,a+b+c=3b\]  or \[a+c=2b.\] \[\therefore \] a, b, care in A.P., also sin A, sin B, sin Care in A.P.


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