A) \[y\pm x=0\]
B) \[y-1=\pm 1(x-1)\]
C) \[x-1=\pm 2(y-1)\]
D) None of these
Correct Answer: B
Solution :
Point of intersection of the lines \[4x-3y-1=0\] and \[2x-5y+3=0\]is \[(1,1)\] |
\[\because \] the lines are equally inclined to the axes. |
\[\therefore \] angles will be either \[45{}^\circ \]or \[135{}^\circ \]. |
Hence, the required equation are \[y-1=\pm 1\left( x-1 \right)\] |
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