A) 0.73 mJ
B) 0.7 mJ
C) 0.8 mJ
D) 8.0 J
Correct Answer: C
Solution :
[c]:At steady state, no current flows through capacitor C. |
According to Kirchhoff?s law, |
(i) at junction \[E,{{I}_{1}}=3A\] |
(ii) at junction \[H,{{I}_{2}}=1A\] |
(iii) Potential difference across capacitor, |
Or |
\[V=(6\times 3)+(2\times 1)=18+2=20V\] |
\[\therefore \]Energy \[=\frac{1}{2}C{{V}^{2}}\] |
Or |
\[U=\frac{1}{2}\times (4\times {{10}^{-6}})\times {{(20)}^{2}}=8\times {{10}^{-4}}J\] |
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