A) 0.01
B) \[0.02\]
C) \[0.03\]
D) \[0.05\]
Correct Answer: D
Solution :
Before connecting voltmeter potential difference across \[400\,\Omega \] resistance is \[{{V}_{i}}=\frac{400}{(400+800)}\times 6=2V\] |
After connecting voltmeter equivalent resistance between A and B \[=\frac{400\times 10,000}{(400+10,000)}=384.6\Omega \] |
Hence, potential difference measured by voltmeter \[{{V}_{f}}=\frac{384.6}{(384.6+800)}\times 6=1.95\,V\] |
Error in measurement \[={{V}_{i}}-{{V}_{f}}=2-1.95=0.05V\] |
You need to login to perform this action.
You will be redirected in
3 sec