JEE Main & Advanced Sample Paper JEE Main - Mock Test - 13

  • question_answer
    The input signal given to a CE amplifier having a voltage gain of 150 is \[{{V}_{i}}=2\cos \left( 15+\frac{\pi }{3} \right)\].The corresponding output signal will be:

    A) \[75\,\cos \left( 15t+\frac{2\pi }{3} \right)\]    

    B) \[2\,\cos \left( 15t+\frac{5\pi }{6} \right)\]

    C) \[300\,\cos \left( 15t+\frac{4\pi }{3} \right)\]

    D) \[300\,\cos \left( 15t+\frac{\pi }{3} \right)\]

    Correct Answer: C

    Solution :

    Given: Voltage gain \[{{A}_{V}}=150\]
    \[{{V}_{i}}=2\cos \left( 15t\frac{\pi }{3} \right);\,\,{{V}_{0}}=?\]
    For CE transistor phase difference between input and output signal is \[\pi =180{}^\circ \]
    Using formula, \[{{A}_{V}}=\frac{{{V}_{0}}}{{{V}_{1}}}\]
    \[\Rightarrow \,\,{{V}_{0}}={{A}_{V}}\times {{V}_{i}}\]
    \[=150\times 2\cos \left( 15t+\frac{\pi }{3} \right)\]
    or         \[{{V}_{0}}=300\cos \left( 15t+\frac{\pi }{3}+\pi  \right)\]
    \[{{V}_{0}}=300\cos \left( 15t+\frac{4}{3}\pi  \right)\]


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