A) \[W=\mu ({{T}_{1}}-{{T}_{2}}){{C}_{P}}\]
B) \[W=\mu ({{T}_{1}}-{{T}_{2}}){{C}_{V}}\]
C) \[W=\mu ({{T}_{1}}+{{T}_{2}}){{C}_{P}}\]
D) \[W=\mu ({{T}_{1}}+{{T}_{2}}){{C}_{V}}\]
Correct Answer: B
Solution :
Work done during an adiabatic change is, \[W=\frac{\mu R({{T}_{1}}-{{T}_{2}})}{\gamma -1}\] \[\gamma =\frac{{{C}_{P}}}{{{C}_{\text{v}}}}\] \[\therefore \,\,\gamma =1=\frac{{{C}_{P}}-{{C}_{\text{v}}}}{{{C}_{\text{v}}}}=\frac{R}{{{C}_{\text{v}}}}\]You need to login to perform this action.
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