For the reduction of \[NO_{3}^{-}\]ion in an aqueous solution,\[E{}^\circ \]is +0.96 V. Values of \[E{}^\circ \] for some metal ions are given below: |
\[{{V}^{2+}}_{(aq)}+2{{e}^{-}}\to V;E{}^\circ =-1.19V\] |
\[{{F}^{3+}}_{(aq)}+3{{e}^{-}}\to Fe;E{}^\circ =-0.04V\] |
\[A{{u}^{3+}}_{(aq)}+3{{e}^{-}}\to Au;E{}^\circ =+1.40V\] |
\[H{{g}^{2+}}_{(aq)}+2{{e}^{-}}\to Hg;E{}^\circ =+0.86V\] |
The pair of metals that is not oxidised by \[NO_{3}^{-}\]in aqueous solution is |
A) V and Hg
B) Hg and Fe
C) Fe and Au
D) Fe and V
Correct Answer: C
Solution :
[c] : The substances which have lower I reduction potentials are strong reducing agents while those which have higher reduction I potentials are stronger oxidising agents. \[\because \]\[E_{{{M}^{n+}}/M}^{o}\]for V Fe and Hg are lower than that of \[NO_{3}^{-},\]so \[NO_{3}^{-}\]will oxidise V, Fe and Hg.You need to login to perform this action.
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