A) \[120\]
B) \[110\]
C) \[100\]
D) \[90\]
Correct Answer: D
Solution :
[d] \[A+B+C=19\] Case I: If A = 2 then number of ways \[{{=}^{18}}{{C}_{1}}\] Case II: If \[A=4\]then number of ways \[{{=}^{16}}{{C}_{1}}\] Case IX: If \[A=18\]then number of ways \[{{=}^{2}}{{C}_{1}}\] \[\therefore \] Total number of ways \[{{=}^{18}}{{C}_{1}}{{+}^{16}}{{C}_{1}}+.....{{+}^{2}}{{C}_{1}}=90\]You need to login to perform this action.
You will be redirected in
3 sec