A) \[\text{1}{{\text{0}}^{3}}\]
B) \[99\times {{10}^{3}}\]
C) \[100\times {{10}^{3}}\]
D) \[101\times {{10}^{3}}\]
Correct Answer: D
Solution :
[d]: Given : \[d=0.28\text{ }mm=0.28\times {{10}^{-3}}m\] \[r=0.14\times {{10}^{-3}}m\] Surface tension, \[S=0.07N{{m}^{-1}}\] Atmospheric pressure \[={{10}^{5}}N\,{{m}^{-2}}\] \[S=\frac{rh\rho g}{2}=0.07\] \[0.07=\frac{P\times 0.14\times {{10}^{-3}}}{2}\]\[(\because P=h\rho g)\] \[P=1\times {{10}^{3}}N{{m}^{-2}}\] Total pressure = P + Atmospheric pressure \[={{10}^{3}}N{{m}^{-2}}+{{10}^{5}}N{{m}^{-2}}\] \[={{10}^{3}}(1+100)N{{m}^{-2}}\] \[=101\times {{10}^{3}}N{{m}^{-2}}\]You need to login to perform this action.
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