A) \[A\cup B\cup C\]
B) \[A\cap (B\cup C)\]
C) \[A\cup (B\cap C)\]
D) \[A\cap (B\cap C)\]
Correct Answer: B
Solution :
[b]: Clearly, \[(A-B)\cup (B-C)\cup (C-A)\] \[=(A\cup B\cup C)-(A\cap B\cap C)\] \[=(A\cap B\cap C){{[\because A\cup B\cup (C-A)]}^{C}}\] \[=\left[ (A\cap B\cap C)' \right]'=A\cap B\cap C\].You need to login to perform this action.
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