A) \[-\pi \]
B) \[\pi \]
C) \[\frac{\pi }{2}\]
D) 1
Correct Answer: B
Solution :
[b]: By L Hospitals Rule, Given limit \[=\underset{x\to 0}{\mathop{\lim }}\,\cos (\pi co{{s}^{2}}x)-(2\pi cosx)\frac{\sin x}{2x}\] \[=(\cos \pi )(-\pi )=\pi \]You need to login to perform this action.
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