A) 1
B) 2
C) - 1
D) - 2
Correct Answer: B
Solution :
[b]: \[\int_{{}}^{{}}{\frac{5\tan x}{\tan x-2}}dx=x+a\ln |\sin x-2\cos x|+k\] On differentiating both sides, we get \[\frac{5\tan x}{\tan x-2}=1+\frac{a(cos\,x+2sin\,x)}{\sin x-2\cos x}\] \[\Rightarrow \]\[\frac{5\sin x}{\sin x-2\cos x}=\frac{\sin x(1+2a)+cos\,x(a-2)}{\sin x-2\cos x}\] \[\Rightarrow \]\[a=2\]You need to login to perform this action.
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