A) - 2
B) -1
C) \[-\frac{1}{2}\]
D) 0
Correct Answer: A
Solution :
: The lines are \[\frac{x-1}{1}=\frac{y+3}{-\lambda }=\frac{z-1}{\lambda }\]and \[\frac{x}{1/2}=\frac{y-1}{1}=\frac{z-2}{-1}\] The lines are coplanar if \[\Rightarrow \]\[-1(\lambda -\lambda )-4\left( -1-\frac{\lambda }{2} \right)+1+\frac{\lambda }{2}=0\] \[\Rightarrow \]\[5+\frac{5\lambda }{2}=0\Rightarrow \lambda =-2\]You need to login to perform this action.
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