question_answer

Fundamental frequency of a stretched sonometer wire is \[{{f}_{0}}\]. When its tension is increased by \[96%\] and length decreased by \[35%,\] its fundamental frequency becomes \[{{\eta }_{1}}\,\,{{f}_{0}}\]. When its tension is decreased by \[36%\] and its length is increased by \[30%,\] its fundamental frequency becomes\[{{\eta }_{2}}\,\,{{f}_{0}}\]. Find \[\frac{{{\eta }_{1}}}{{{\eta }_{2}}}\].

Answer:

3.5