A) \[3.66%\]
B) \[3.9%\]
C) \[2.12%\]
D) \[0.008%\]
Correct Answer: A
Solution :
\[{{\wedge }^{\infty }}_{C{{H}_{3}}COOH}=390.71\,oh{{m}^{-1}}c{{m}^{2}}e{{q}^{-1}}\] |
\[{{\wedge }^{\infty }}_{C{{H}_{3}}COOH}=14.3\,oh{{m}^{-1}}c{{m}^{2}}e{{q}^{-1}}\] |
Degree of dissociation \[(\alpha )=\frac{{{\wedge }^{c}}}{{{\wedge }^{\infty }}}\] |
\[=\frac{14.3}{390.71}=0.0366\] i.e. \[3.66%\] |
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