JEE Main & Advanced Sample Paper JEE Main - Mock Test - 15

  • question_answer
    An ideal massless spring s can be compressed \[1.0\text{ }m\] by a \[100\text{ }N\]force. It is placed as shown at the bottom of a frictionless inclined plane which makes an angle of \[\theta =30{}^\circ \] with the horizontal. A 10 kg block is released from rest from the top of the incline and is brought to rest momentarily after compressing the spring\[2.0\text{ }m\]. Through what distance does the mass slide before coming to rest along the inclined surface?

    A) \[4m\]                    

    B) \[6m\]                    

    C) \[1m\]                    

    D) \[2m\]

    Correct Answer: D

    Solution :

    [d] Spring constant \[=100\text{ }N/m\] Conserving energy, \[mg\,\left( x+2 \right)\sin 30{}^\circ =\frac{1}{2}K.{{(2)}^{2}}\] \[10\times 10\left( x+2 \right)\times \frac{1}{2}=\frac{1}{2}\times 100\times 4\] \[x+2=4\] \[x=2\text{ }m\]along the inclined surface.

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