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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 15

  • question_answer
    \[\underset{x\to 0}{\mathop{\lim }}\,\frac{\sin (\pi co{{s}^{2}}x)}{{{x}^{2}}}=\]

    A) \[-\pi \]              

    B) \[\pi \]

    C) \[\frac{\pi }{2}\]            

    D)  1

    Correct Answer: B

    Solution :

    [b]: By L Hospitals Rule, Given limit \[=\underset{x\to 0}{\mathop{\lim }}\,\cos (\pi co{{s}^{2}}x)-(2\pi cosx)\frac{\sin x}{2x}\] \[=(\cos \pi )(-\pi )=\pi \]


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