A)
B)
C)
D)
Correct Answer: C
Solution :
[c] Velocity of stream at height h will be given as \[{{v}^{2}}={{v}_{0}}^{2}+2gh\] or \[v=\sqrt{v_{0}^{2}+2gh}\] From continuity law, \[{{v}_{0}}A=va\] or \[a=\frac{{{v}_{0}}A}{v}\] or \[a=\frac{{{v}_{0}}A}{\sqrt{v_{0}^{2}+2gh}}\]You need to login to perform this action.
You will be redirected in
3 sec