A) \[16:9\sqrt{3}\]
B) \[16\sqrt{3}:9\]
C) \[16:1\]
D) \[1:16\]
Correct Answer: A
Solution :
[a] \[T=2\pi \sqrt{\frac{I}{MB\,\,\cos \theta }}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{B}_{2}}\cos {{\theta }_{2}}}{{{B}_{1}}\cos {{\theta }_{1}}}}\Rightarrow \frac{{{B}_{1}}}{{{B}_{2}}}=\frac{16}{9\sqrt{3}}\]You need to login to perform this action.
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