A) \[\frac{\sqrt{2}q}{\sqrt{3\pi {{\varepsilon }_{0}}m{{a}^{3}}}}\]
B) \[\frac{q}{\sqrt{3\pi {{\varepsilon }_{0}}m{{a}^{3}}}}\]
C) \[\frac{\sqrt{2}q}{\sqrt{6\pi {{\varepsilon }_{0}}m{{a}^{3}}}}\]
D) \[\frac{q}{\sqrt{6\pi {{\varepsilon }_{0}}m{{a}^{3}}}}\]
Correct Answer: D
Solution :
[d] \[\Delta U+\Delta KE=0\] \[\frac{1}{2}(2m{{a}^{2}}){{\omega }^{2}}=\frac{2k{{q}^{2}}}{3a}\] \[\omega =\sqrt{\frac{2k{{q}^{2}}}{3m{{a}^{2}}}}=\frac{q}{\sqrt{6\pi {{\varepsilon }_{0}}m{{a}^{3}}}}\]You need to login to perform this action.
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