JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    A parallel plate air capacitor is charged by a battery of emf \[\varepsilon \], then it is disconnected from the battery and allowed to discharge through a dielectric slab of dielectric constant K and resistivity \[\rho ,\] as shown in figure. There is a uniform outward magnetic field B at the location of the capacitor. The total momentum attained by the slab after complete discharge is

    A) \[\frac{\varepsilon {{\ell }^{2}}B}{\rho }\]         

    B)        \[B{{\varepsilon }_{0}}K{{\ell }^{2}}\varepsilon \]

    C) \[\frac{\varepsilon {{\ell }^{2}}B}{K\rho }\]       

    D)        \[B{{\varepsilon }_{0}}{{\ell }^{2}}\varepsilon \]

    Correct Answer: D

    Solution :

    [d] Impulse \[=\int{idB}\,\,(dt)\] \[dB\Delta q=\frac{dB{{\varepsilon }_{0}}{{\ell }^{2}}\varepsilon }{d}=B{{\varepsilon }_{0}}{{\ell }^{2}}\varepsilon \]


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