A) 2
B) \[\frac{3}{2}\]
C) 1
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
[b]:\[y'=\frac{a}{x}+2bx+1,y'(-1)=0,y'(2)=0\] \[\Rightarrow \]\[-a-2b+1=0,\frac{a}{2}+4b+1=0\] \[\Rightarrow \]\[a=2,b=-\frac{1}{2}\Rightarrow a+b=\frac{3}{2}\].You need to login to perform this action.
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