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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    If \[0.5\text{ }mol\]of \[BaC{{l}_{2}}\] is mixed with \[0.2\]mole of \[N{{a}_{3}}P{{O}_{4}},\] find the maximum amount of \[B{{a}_{3}}{{(P{{O}_{4}})}_{2}}\] that can be formed.

    A) 1 mole  

    B)        \[0.5\]mole 

    C) \[0.1\] mole       

    D)        \[0.01\] mole

    Correct Answer: C

    Solution :

     
                    \[3BaC{{l}_{2}}+2N{{a}_{3}}P{{O}_{4}}\to 6NaCl+B{{a}_{3}}{{(P{{O}_{4}})}_{2}}\]
    Molar ratio 3 2 6 1
    Initial moles \[0.5\] \[0.2\] 0 0
    Limiting reagent is \[N{{a}_{3}}P{{O}_{4}}\] hence it would be consumed, and the yield would be decided by it initial moles. 2 moles of \[N{{a}_{3}}P{{O}_{4}}\] give 1 mole of  \[B{{a}_{3}}{{(P{{O}_{4}})}_{2}},\] \[\therefore \] \[0.2\] moles of \[N{{a}_{3}}P{{O}_{4}}\] would give \[0.1\] mole of \[B{{a}_{3}}{{(P{{O}_{4}})}_{4}}\]


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