A) f(x) is continuous at x = 1
B) \[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)=lo{{g}_{e}}3\]
C) \[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)=-\sin 1\]
D) \[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)\]does not exist
Correct Answer: C
Solution :
[c] : For \[|x|<1,{{x}^{2n}}\to 0\]as\[n\to \infty \] \[|x|>1,\frac{1}{{{x}^{2n}}}\to 0\]as\[n\to \infty \] \[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,(f)(x)=-sin1;\underset{x\to {{1}^{-}}}{\mathop{\lim }}\,f(x)=log3\]You need to login to perform this action.
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