JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    Prussian blue is formed when

    A) Ferrous sulphate reacts with \[FeC{{l}_{3}}\]

    B) Ferric chloride reacts with \[{{K}_{4}}[Fe{{(CN)}_{6}}]\]

    C) Ferrous ammonium sulphate reacts with \[FeC{{l}_{3}}\]

    D) Ammonium sulphate reacts with \[FeC{{l}_{3}}\]

    Correct Answer: B

    Solution :

    \[4FeC{{l}_{3}}+3{{K}_{4}}[Fe{{(CN)}_{6}}]\to {{K}_{4}}{{[Fe{{(CN)}_{6}}]}_{3}}\underset{\text{Prussian}\,\,\text{blue}}{\mathop{+12KCl}}\,\]


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