A) Directly proportional to distance from \[O\]
B) Directly proportional to square of distance from \[O\]
C) Inversely proportional to distance from \[O\]
D) Inversely proportional to square of distance from \[O\]
Correct Answer: C
Solution :
[c] \[\oint{\vec{E}.\overrightarrow{dl}}\] along ABDCA \[{{E}_{1}}R\alpha -{{E}_{2}}r\alpha =0\] \[\Rightarrow \,\,\,{{E}_{1}}R={{E}_{2}}r\,\,\,\,\,\,\Rightarrow E\propto \frac{1}{R}\]You need to login to perform this action.
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