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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 16

  • question_answer
    If \[\sin x\frac{dy}{dx}+y\cos x=x\sin x,\]then\[(y-1)sinx=\]

    A) \[c-x\sin x\]       

    B) \[c+x\cos x\]

    C) \[c-x\cos x\]       

    D) \[c+x\sin x\]

    Correct Answer: C

    Solution :

    [c] \[\frac{d}{dx}(sin\,x.y)=x\,sin\,x\] \[\therefore \]\[y\sin x=\int_{{}}^{{}}{x\,\sin x\,dx}=-x\,\cos x+\sin x+c\] \[\Rightarrow \]\[(y-1)sinx=c-x\,cos\,x.\]


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