A) x
B) 1
C) f(x)
D) g(x)
Correct Answer: B
Solution :
[b]: The given functions are \[g(x)=1+x-[x]\] and We see that \[g(x)=1+x-[x]=1+(x-[x])\] \[=1+\{c\}\ge 1(\because 0\le \{x\}<1)\] \[\therefore \]\[f(g(x))=1\]for all xYou need to login to perform this action.
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