A) \[\frac{{{W}_{1}}}{S}\]
B) \[\frac{{{W}_{1}}+(W/4)}{S}\]
C) \[\frac{{{W}_{1}}+(3W/4)}{S}\]
D) \[\frac{{{W}_{1}}+W}{S}\]
Correct Answer: C
Solution :
Total force at height \[3L/4\] from its lower end = Weight suspended + Weight of \[3/4\] of the wire \[={{W}_{1}}+(3W/4)\] Hence stress \[=\frac{{{W}_{1}}+(3W/4)}{S}\]You need to login to perform this action.
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