A) \[CaO,CaC{{O}_{3}}\]
B) \[CaO,N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{a}_{2}}C{{O}_{3}},CaO\]
D) \[NaHC{{O}_{3}},CaC{{l}_{2}}\]
Correct Answer: B
Solution :
[b]: Temporary hardness is due to dissolved \[HCO_{3}^{-}\]of\[C{{a}^{2+}}\]and\[M{{g}^{2+}}\]. \[CaO+{{H}_{2}}O\xrightarrow[{}]{{}}Ca{{(OH)}_{2}}\] \[Ca{{(HC{{O}_{3}})}_{2}}+Ca{{(OH)}_{2}}\xrightarrow[{}]{{}}2CaC{{O}_{3}}\downarrow +2{{H}_{2}}O\] Permanent hardness is due to dissolved \[C{{l}^{-}}\]and \[SO_{4}^{2-}\]of \[C{{a}^{2+}}\]and\[M{{g}^{2+}}\] \[CaC{{l}_{2}}+N{{a}_{2}}C{{O}_{3}}\xrightarrow[{}]{{}}CaC{{O}_{3}}\downarrow +2NaCl\] \[CaS{{O}_{4}}+N{{a}_{2}}C{{O}_{3}}\xrightarrow[{}]{{}}CaC{{O}_{3}}\downarrow +N{{a}_{2}}S{{O}_{4}}\]
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