JEE Main & Advanced Sample Paper JEE Main - Mock Test - 17

  • question_answer
    Consider the following equilibrium in a closed container, \[{{N}_{2}}{{O}_{4(g)}}2N{{O}_{2(g)}}\]. At a fixed temperature, the volume of the reaction mixture is halved. For this change, which of the following statements holds true regarding the equilibrium constant\[({{K}_{p}})\]and degree of dissociation \[(\alpha )\]?

    A) Neither\[({{K}_{p}})\]  nor \[\alpha \] changes.

    B) Both \[{{K}_{p}}\]and\[\alpha \] change.

    C) \[{{K}_{p}}\]changes but\[\alpha \]does not.

    D) \[{{K}_{p}}\]does not change but\[\alpha \]changes

    Correct Answer: D

    Solution :

    [d]: \[{{K}_{P}}\]is constant at constant temperature. As volume is halved, pressure will be doubled. Hence, equilibrium will shift in the backward direction, i.e., degree of dissociation decreases.


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