A) \[{{2}^{4}}\]
B) \[{{3}^{4}}\]
C) \[{{4}^{3}}\]
D) None of these
Correct Answer: B
Solution :
[b] For each element of set A, there are 3 possibilities i.e.,(i) element of B but not element of C |
(ii) element of C but not element of B |
(iii) neither element of B nor element of C |
So, number of ways\[={{3}^{4}}\] |
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