| The correct order of bond order values among the following species is |
| (i) \[N{{O}^{-}}\] |
| (ii) \[N{{O}^{+}}\] |
| (iii) NO |
| (iv) \[N{{O}^{2+}}\] |
A) (i) < (iv) < (iii) < (ii) < (v)
B) (iv) = (ii) < (i) < (v) < (iii)
C) (v) < (i) < (iv) = (iii) < (ii)
D) (ii) < (iii) < (iv) < (i) < (v)
Correct Answer: C
Solution :
[c] : (iii) NO (15): \[KK\sigma 2{{s}^{2}}\sigma *2{{s}^{2}}\sigma 2p_{z}^{2}\pi 2p_{x}^{2}\] \[=\pi 2p_{y}^{2},\pi *2p_{x}^{1}\] Bond order \[=\frac{1}{2}(8-3)=2.5\] (iv) \[N{{O}^{2+}}:\] Bond order\[=\frac{1}{2}(7-2)=2.5\] (ii)\[~N{{O}^{+}}:\] Bond order \[=\frac{1}{2}(8-2)=3.0\] (i)\[N{{O}^{-}}:\] Bond order\[=\frac{1}{2}(8-4)=2.0\] (v) \[N{{O}^{2-}}:\] Bond order \[=\frac{1}{2}(8-5)=1.5\] Hence, the correct order is \[\underset{(v)}{\mathop{N{{O}^{2-}}}}\,<\underset{(i)}{\mathop{N{{O}^{-}}}}\,<\underset{(vi)}{\mathop{N{{O}^{2+}}}}\,=\underset{(iii)}{\mathop{NO}}\,<\underset{(ii)}{\mathop{N{{O}^{+}}}}\,\]
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