A) 4
B) 5
C) 6
D) 7
Correct Answer: A
Solution :
[a] \[{{\sin }^{-1}}(\sin 6x)=x\] \[\Rightarrow \,\,\,\sin 6x=\sin x\] \[\Rightarrow \,\,\,x=\frac{\pi }{7},\frac{3\pi }{7},\frac{5\pi }{7},\pi ,0,\frac{2\pi }{5},\frac{4\pi }{5}\] But \[\frac{5\pi }{7},\pi \] and\[\frac{4\pi }{5}\] are rejected as any value of x which is solution of given equation can't exceed \[\frac{\pi }{2}\] .
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