A) \[2gH={{n}^{2}}{{u}^{2}}\]
B) \[gH={{(n-2)}^{2}}{{u}^{2}}d\]
C) \[2gH=n{{u}^{2}}(n-2)\]
D) \[gH=(n-2){{u}^{2}}\]
Correct Answer: C
Solution :
Speed on reaching ground \[v=\sqrt{{{u}^{2}}+2gh}\] Now, \[v=v+at\] \[\Rightarrow \,\,\sqrt{{{u}^{2}}+2gh}=-u+gt\] Time taken to reach highest point is \[t=\frac{u}{g},\] \[\Rightarrow \,\,t=\frac{u+\sqrt{{{u}^{2}}+2gH}}{g}=\frac{nu}{g}\](from question) \[\Rightarrow \,\,2gH=n(n-2){{u}^{2}}\]You need to login to perform this action.
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