A) 120
B) 720
C) 540
D) 210
Correct Answer: D
Solution :
[d] Sum of the coefficients of terms of degree 13 in the expansion of \[{{(1+x)}^{11}}{{(1+{{y}^{2}}-z)}^{10}}\] = Coefficient of \[{{t}^{13}}\] in \[{{(1+t)}^{11}}{{(1+{{t}^{2}}-t)}^{10}}\] = Coefficient of \[{{t}^{13}}\] in \[{{(1+{{t}^{3}})}^{10}}(1+t)\] = Coefficient of \[{{t}^{13}}\]in \[[{{(1+{{t}^{3}})}^{10}}+t{{(1+{{t}^{3}})}^{10}}]\] = Coefficient of \[{{t}^{12}}\] in \[{{(1+{{t}^{3}})}^{10}}{{=}^{10}}{{C}_{4}}\]
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