(I) Path is feasible, whereas path is not |
(II) Path is feasible, whereas path is not |
(III) The \[Cl\]of undergoes \[SN\]reaction because it is activated by the two EWG \[(-N{{O}_{2}})\] groups. |
(IV) The nitration of (Z) does not give (V) but it gives |
because the first nitro groups is deactivated, so the second nitro group enters the other ring |
A) I
B) II
C) I, III, IV
D) I, IV
Correct Answer: C
Solution :
[c] Factual statementYou need to login to perform this action.
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