A) \[6,\text{ }3\]
B) \[3,\,\,6\]
C) \[6,\,\,4\]
D) \[4,\,\,6\]
Correct Answer: A
Solution :
[a] In rutile \[(Ti{{O}_{2}})\] each \[T{{i}^{4+}}\] ion is octahedrally surrounded by six \[{{O}^{2-}}\]ions whereas each \[{{O}^{2-}}\] ion is surrounded by only there \[T{{i}^{4+}}\] ions, arranged at the there comers of a plane triangle. The C.N. of \[T{{i}^{4+}}\] and \[{{O}^{2-}}\] ion are 6 and 3 respectively. Formula is \[T{{i}_{3}}^{4+}{{O}_{6}}^{2-}\Rightarrow 2Ti{{O}_{2}}\] CN of cation = Number of anions CN of anion = number of cations
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