A) 4
B) 6
C) 1
D) 2
Correct Answer: A
Solution :
\[(\sin x+3)\,(2\sin x-1)=0\] \[\Rightarrow \,\,\sin x=\frac{1}{2}\] and \[\sin x\ne -3\] \[\therefore \,\] In \[\left[ 0,3\pi \right],\] x has 4 values.You need to login to perform this action.
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