A) 3.8 mm
B) 1.6 mm
C) 7.6 mm
D) 3.2 mm
Correct Answer: D
Solution :
[d] \[\Delta x=\frac{D(\mu -1)t}{d}.\]Also \[\Delta x=\frac{nD\lambda }{d}.\] \[\therefore \]\[\frac{D(\mu -1)t}{d}=\frac{nD\lambda }{d}\]or\[(\mu -1)t=n\lambda \] or\[\frac{{{t}_{1}}}{{{t}_{2}}}=\frac{{{t}_{1}}}{{{t}_{2}}}\Rightarrow {{t}_{2}}=\frac{{{n}_{2}}{{t}_{1}}}{{{n}_{1}}}\]or\[{{t}_{2}}=\frac{20\times 4.8}{30}=3.2mm.\]You need to login to perform this action.
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