A) 5
B) 4
C) 3
D) 8
Correct Answer: D
Solution :
After first half hrs \[N={{N}_{0}}\frac{1}{2}\] for \[t=\frac{1}{2}\] to \[t=1\frac{1}{2}\] \[N=\left( {{N}_{0}}\frac{1}{2} \right){{\left[ \frac{1}{2} \right]}^{4}}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{5}}\] for \[t=1\frac{1}{2}\]to \[t=2\] hrs. [for both A and B \[\frac{1}{{{t}_{1/2}}}=\frac{1}{1/2}+\frac{1}{1/4}=2+4=6;\] \[{{t}_{1/2}}=1/6hrs]\] \[N=\left[ {{N}_{0}}{{\left( \frac{1}{2} \right)}^{5}} \right]{{\left( \frac{1}{2} \right)}^{3}}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{8}}\]You need to login to perform this action.
You will be redirected in
3 sec