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JEE Main & Advanced Sample Paper JEE Main - Mock Test - 19

  • question_answer
    A square surface of side L meter in the plane of the paper is placed in a uniform electric field E (volt/m) acting along the same plane at an angle Q with the horizontal side of the square as shown in Figure. The electric flux linked to the surface, in units of volt. w, is

    A) \[E{{L}^{2}}\]            

    B)        \[E{{L}^{2}}\,\cos \theta \]

    C) \[E{{L}^{2}}\,sin\theta \]                     

    D) zero

    Correct Answer: D

    Solution :

    Electric flux, \[\phi =EA\cos \theta ,\] where \[\theta =\] angle between E and normal to the surface. Here \[\theta =\frac{\pi }{2}\] \[\Rightarrow \,\,\,\phi =0\]


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