A) \[3x+|{{f}^{-1}}(x)|=2{{f}^{-1}}(x)\]
B) \[x+|{{f}^{-1}}(x)|=2{{f}^{-1}}(x)\]
C) \[{{f}^{-1}}(x)-|x|=2x\]
D) \[3x-|{{f}^{-1}}(x)|=2{{f}^{-1}}(x)\]
Correct Answer: D
Solution :
[d] \[x+|f(x)|=2f(x)\] \[\Rightarrow \,\,\,\,\,\,\,3x-|{{f}^{-1}}(x)|=2{{f}^{-1}}(x)\]You need to login to perform this action.
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