A) \[1.00\]
B) \[1.02\]
C) \[1.04\]
D) \[0.98\]
Correct Answer: A
Solution :
Energy emitted/sec by \[{{S}_{1}},{{P}_{1}}={{n}_{1}}\frac{hc}{{{\lambda }_{1}}}\] Energy emitted/sec by \[{{S}_{2}},{{P}_{2}}={{n}_{2}}\frac{hc}{{{\lambda }_{2}}}\] \[\therefore \,\,\frac{{{P}_{2}}}{{{P}_{1}}}=\frac{{{n}_{2}}}{{{n}_{1}}}.\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{1.02\times {{10}^{15}}}{{{10}^{15}}}.\frac{5000}{5100}=1.0\]You need to login to perform this action.
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