A) \[515Hz,486Hz\]
B) \[486Hz,515Hz\]
C) \[510Hz,490Hz\]
D) \[490Hz,510Hz\]
Correct Answer: B
Solution :
Here the observer is at rest with respect to the medium and the source is going away from the observer. The apparent frequency heard by the observer is, therefore, \[v'=\frac{v}{v+{{v}_{s}}}v=\frac{340}{340+10}\times 500Hz\] \[v'=486Hz\] The frequency received by the wall is \[v''=\frac{v}{v-{{v}_{s}}}v=\frac{340}{340-10}\times 500=515Hz\] The wall reflects this sound without changing the frequency. Thus, the frequency of the reflected wave as heard by the ground observer is \[515\text{ }Hz\]You need to login to perform this action.
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